DTC Diagnosis Vehicle Work Items and Spare Parts Retrieval Method Based on Decision Tree Classification
A decision tree classification and fault code technology, applied in the field of information retrieval, can solve problems such as maintenance labor costs for detailed solutions to failures, and achieve the effect of solving the problem of limited experience
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Embodiment 1
[0012] Example 1 : A fault code diagnosis vehicle item and spare parts retrieval method based on decision tree classification, including
[0013] Step 1. Collect vehicle information data;
[0014] Step 2. Analyze the vehicle VIN code to obtain variables, and the variables include engine displacement, body type, and engine gearbox type obtained by VIN code analysis;
[0015] Step 3. Perform a decision tree analysis on the spare part codes corresponding to the variables, complete the classification of variable data to form spare part information, and establish an index to form a diagnostic knowledge base;
[0016] Step 4. Create a language model, set up a cell thesaurus, cut words in the cell thesaurus to retrieve the cell words, and arrange the cell words, and use the decision classification of the decision tree model to form a diagnostic database for the corresponding work item of the fault code;
[0017] Step 5. Associate the diagnostic database with the diagnostic knowled...
Embodiment 2
[0019] Example 2: Have the same technical scheme as embodiment 1, more specifically, for step 4 of embodiment 1,
[0020] In the step 3, the historical records of the maintenance spare parts table are used as the data basis, and the spare parts are classified through the decision tree model, and the maintenance spare parts table sample is shown in Table 1:
[0021] Table I
[0022]
[0023]
[0024] The basic principles of the decision tree model are as follows:
[0025] First: Determine the entropy of different categories of spare parts in each dimension. Taking VIN4 as an example, the entropy is defined as
[0026] E=sum(-p(I)*log(p(I)))
[0027] Wherein I=1:N (N category results, such as this example 1, that is, the spare part belongs to this model, so the probability P(I)=1)
[0028] Then E(5)=-(1 / 1) Log2(1 / 1)-(0 / 1) Log2(0 / 1)=0+0=0
[0029] E(3)=-(1 / 1) Log2(1 / 1)-(0 / 1) Log2(0 / 1)=0+0=0
[0030] E(4)=-(1 / 1) Log2(1 / 1)-(0 / 1) Log2(0 / 1)=0+0=0
[0031] If the entropy...
Embodiment 3
[0048] Example 3: Have the same technical scheme as embodiment 1 or 2, more specifically, for step 4 of embodiment 1,
[0049] The creation of the language model in the step 4 and the establishment of the cell lexicon include the following steps:
[0050] S1.1 Collect professional fault description language;
[0051] S1.2 Perform word vector decomposition on the professional fault description language.
[0052] The creation of the language model is based on the assumption that the occurrence of the nth cell word is only related to the previous n-1 cell words; the calculation formula for the occurrence weight of the fault description sentence T is:
[0053] P(T)=P(w 1 ,w 2 ,w 3 ,...,w n )
[0054] =P(w 1 )×P(w 2 |w 1 )×P(w 3 |w 1 ,w 2 )×…×P(w n |w 1 ,w 2 ,...,w n-1 )
[0055] ≈P(w 1 )×P(w 2 |w 1 )×P(w 3 |w 2 )…P(w n |w n-1 );
[0056] Wherein, P(T) is the weight of the fault description sentence T, P(w n |w 1 ,w 2 ,...,w n-1) is the weight of the ...
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