Method for selecting capacity by voltage of lithium ion battery and its application
A lithium-ion battery, charging capacity technology, applied in the field of lithium-ion batteries, can solve the problems of long charging and discharging time, prone to misjudgment, large test error, etc., to reduce the number of equipment and labor, reduce energy loss, and misjudgment low probability effect
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Embodiment 1
[0057] This embodiment relates to a type A battery with a nominal capacity of 3100mAh, which adopts a high-temperature precharging process at 50°C. After precharging, the voltage is used to select the capacity at 50°C. The target voltage for shipment is 3.90V-3.95V.
[0058] (1) At a temperature of 50±2°C, use a constant current of 0.05C A to charge for 91 minutes, use a current of 0.5C A to charge to 4.35V with a constant current and constant voltage, and a cut-off current of 0.02C A to measure the charging capacity C 0 ;
[0059] (2) Move the battery to a normal temperature environment, and after 5 hours of storage, use a 0.5C A current to discharge to 3.0V, and the discharge capacity is C 1 , and use C 0 with C 1 The difference is divided by the discharge capacity C 1 Find the first loss c%;
[0060] (3) At room temperature, charge the battery with 0.5C A constant current and constant voltage to 3.90V (voltage lower limit), cut-off current 0.02C A, and the measured char...
Embodiment 2
[0074] This embodiment relates to a B-type battery with a nominal capacity of 2200mAh. It uses a 75°C high-temperature precharge process. After the precharge is completed, the voltage is used to select the capacity under the condition of 75°C. The shipping target voltage is 3.95V-4.00V.
[0075] (1) At a temperature of 75±2°C, charge with a constant current of 0.05C A for 91 minutes, charge with a constant current and constant voltage of 1.0C A to 4.35V, cut off the current at 0.02C A, and measure the charging capacity C 0 ;
[0076] (2) Move the battery to a normal temperature environment, and after 5 hours of storage, use a 0.5C A current to discharge to 3.0V, and the discharge capacity is C 1 , and use C 0 with C 1 The difference is divided by the discharge capacity C 1 Find the first loss c%;
[0077] (3) At room temperature, charge the battery with 0.5C A constant current and constant voltage to 3.90V (voltage lower limit), cut-off current 0.02C A, and the measured ch...
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