Anti-harmonic capacitor
A technology of capacitors and harmonics, applied in the direction of structurally fixed capacitor combinations, etc., can solve the problems of high cost, inconvenient installation, and poor applicability of anti-harmonic components, and achieve the effect of small size, convenient installation, and strong applicability
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Embodiment 1
[0038] refer to figure 1 , figure 2 , Figure 5 ~ Figure 8 , an anti-harmonic capacitor, comprising a shell 7 and a three-phase capacitor 5 installed in the shell 7, the shell 7 is provided with a three-phase terminal 1 and a ground terminal 2, and each phase terminal is connected to the capacitor 5 respectively, so The anti-harmonic capacitor also includes a reactor 3 made of an amorphous alloy, the reactor 3 is located in the housing 1, and each phase terminal is connected to one end of the reactor 3, and the reactor The other end of 3 is connected to the capacitor 5 .
[0039] The reactor 3 is a ring-shaped inductor core. The capacitors 5 are connected in a delta shape. Filler 4 is filled in the casing, connecting wires 6 are used to connect between the terminal and the reactor, between the reactor and the capacitor, and between the capacitors.
[0040] Calculation of various parameters of the reactor in the anti-harmonic capacitor, calculation of three-phase compens...
Embodiment 2
[0060] refer to Figure 3-Figure 8 , The capacitors of the present invention are connected in a star shape, and N-phase terminals 8 are arranged on the outer casing, and the N-phase terminals 8 are respectively connected to each capacitor.
[0061] 0.25kv / 10kvar phase-separated compensation power capacitor calculation:
[0062] Rated voltage: 0.25KV
[0063] Rated capacity: 10Kvar
[0064] Rated frequency: 50Hz
[0065] Calculation of capacitance:
[0066] Q=UI*3;
[0067] I=0.314×C×U / 3
[0068] C=Q / 3×0.314×U×U
[0069] In the above formula, Q is the compensation capacitance in Kvar, U is the operating voltage in KV, I is the compensation current in A, and C is the capacitance value in uF. In the formula, 0.314=2∏f / 1000. According to the above formula, it can be calculated:
[0070] Ic=13.3A
[0071] C=169uF
[0072] The reactance value is calculated according to 6% of the capacitor capacity:
[0073] Qc=3UI
[0074] Ql=Qc×6% / 3
[0075] Ql=I×I×2∏fl / 3
[0076] l=Q...
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