Five-particle Brown state-based quantum grouping multi-user secret comparison method
A particle and quantum technology, applied in the field of quantum group secret comparison based on the five-particle Brown state, can solve the problem that parallel comparison of two groups of multiple users cannot be realized at the same time
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Embodiment 1
[0149] Without loss of generality, take 3-bit secret information as an example. Suppose Alice 1 The secret message is 100, Alice 2 The secret message is 010, Bob 1 The secret message is 001, Bob 2 The secret message is 001. Simultaneously let TP pair A 2 (B 2 ) The operation done by the particle is I,X,I(X,I,X), and the final measurement result is {|0>,|1>,|1>}. And Alice 1 The final test result is 101, Alice 2 The final measurement was 011; Bob 1 The final measurement was 011, Bob 2 The measured result is 101. Then the participants encode their information, specifically Alice 1 ,Alice 2 ,Bob 1 and Bob 2The encoded information is 001, 001, 010, 100 respectively. Then send the final encoding result to TP, TP can obtain 000 by comparing the information of group A, and correct it, and the comparison result after correction is 001, which shows that the secret information of group A is different; by comparing the information of group B By comparison, 110 can be obta...
Embodiment 2
[0151] Not general, suppose there are 3 users in group A, named Alice 1 ,Alice 2 ,Alice 3 , each user has 3bit secret information, which are 010, 110,000 in turn; group B has 4 users, namely Bob 1 ,Bob 2 ,Bob 3 ,Bob 4 , and each user also has 3bit secret information, which are 101, 101, 101, 101 in turn. A in the 3 Brown states prepared by TP pair 2 A 3 B 2 B 3 B 4 The unitary operations used by the particles are IXXIX, IIIXX, and XXXII in sequence, and the final measurement result of TP on the particle TP is 101. In addition Alice 1 ,Alice 2 ,Alice 3 ,Bob 1 ,Bob 2 ,Bob 3 ,Bob 4 The measurement results are 001, 010, 100, 100, 100, 110, 010 in sequence, and the information encoded by each user is 011, 100, 100, 001, 001, 011, 111 in sequence, and then the encoded information is passed through the classical channel Pass back to TP. After comparison, TP obtains the pairwise comparison results of group A, taking Alice 1 &Alice 2 ,Alice 1 &Alice 3 ,Alice 2 &...
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