Fast divider with 127 multiplied with 2n as divisor
A fast and powerful technology, applied in instruments, electrical digital data processing, digital data processing components, etc., can solve the problems of many components, slow operation speed, complex structure, etc., to achieve low cost, simple structure, and fewer components. Effect
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Embodiment 1
[0019] A dividend is 0~8191×2 n +2 n -1, the divisor is 127×2 n , a divider with fast operation when n=0. Its circuit schematic diagram is as figure 1shown. The connection relationship of the circuit is: I1, I2, I3, I4, I5, I6, I7, I8, I9, I10, I11, I12, and I13 are the input terminals of the divider, which constitute the binary dividend I1I2I3I4I5I6I7I8I9I10I11I12I13; The Y6 pin, Y5 pin, Y4 pin, Y3 pin, Y2 pin, Y1 pin, X7 pin, X6 pin, X5 pin, X4 pin, X3 pin, X2 pin, X1 pin, I1, I2, I3, I4, I5 and I6 are simultaneously connected to the X6 pin, X5 pin, X4 pin, X3 pin, X2 pin, and X1 pin of the addition ADD617, and are also connected to the input pin 1 of the exclusive OR gate XR1, XR2, XR3, XR4, XR5, and XR6. I7 is connected to the input pin 1 of the AND gate A1, and I8, I9, I10, I11, I12, and I13 are simultaneously connected to the input pins 2 of the exclusive OR gates XR1, XR2, XR3, XR4, XR5, and XR6; the exclusive OR gates XR1, XR2, The output pins 3 of XR3, XR4, XR5,...
Embodiment 2
[0026] The dividend is 0~16383, and the divisor is 127×2 n , when n=1, the circuit schematic diagram of the fast operation divider is as follows figure 2 shown. The connection relationship of the circuit is in figure 1 A connection line I141-O141 from input to output is added on the basis of . When the ADD7618 uses a seven-digit binary number plus a seven-digit binary number plus a one-bit binary number, and the sum is an eight-bit binary adder, all positions other than the lowest six bits of the second addend are 0. Other circuit connections are the same as in Embodiment 1.
[0027] When I1I2I3I4I5I6I7I8I9I10I11I12I13I141=(11000000000010)B=(12290)D, because X7, X6, X5, X4, X3, X2, X1 of ADD7618 constitute the first addend of ADD7618, Y6, Y5, Y4, Y3, Y2 of ADD7618 , Y1 forms the second addend of ADD7618, the first addend of ADD7618 is (0000001)B like this, the second addend is (110000)B, (0000001)B+(110000)B=(00110001)B, Get F8 of ADD7618 to be 0, so just constitute the ...
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