Power distribution network affine state estimation method
A state estimation and distribution network technology, applied in the field of distribution network, can solve problems such as fault location deviation, three-phase load imbalance, small section line faults, etc., to restore power, reduce fault intervals, and increase manpower and material resources Effect
- Summary
- Abstract
- Description
- Claims
- Application Information
AI Technical Summary
Problems solved by technology
Method used
Image
Examples
Embodiment 1
[0045] A distribution network affine state estimation method, such as figure 1 shown, including:
[0046] Step S1. At the head end of the distribution network, perform fault distance acquisition operations on the fault phase and the first normal phase to obtain the first fault distance L 1 .
[0047] It should be noted that the first end of the distribution network is the end of the distribution power output, and the first fault distance L 1 is the lower bound of the first fault interval. By adopting the fault distance obtaining operation, the obtained fault distance is generally smaller than the distance from the tested end to the actual fault point.
[0048] Step S2. At the end of the distribution network, perform a fault distance acquisition operation on the fault phase and the first normal phase to obtain the second fault distance L 2 .
[0049] It should be noted that the end of the distribution network is the receiving end of the distributed power, and the second fa...
Embodiment 2
[0090] Assume that the fault point is 15km away from the head end.
[0091] Through the above fault distance obtaining operation, the first fault interval [14.990km, 15.010km] and the second fault interval [14.995km, 15.015km] are obtained. Through affine number conversion, the first affine number 15.000+0.010ε is obtained 1 and the second affine number 15.005+0.010ε 1 , where ε 1The value range of is [-1,1].
[0092] Obtain the third affine number 15.0025+0.010ε based on the first affine number and the second affine number 1 , where ε 1 The value range of is [-1,1]. Then the third fault interval [14.9925km, 15.0125km] is obtained.
PUM
Abstract
Description
Claims
Application Information
- R&D Engineer
- R&D Manager
- IP Professional
- Industry Leading Data Capabilities
- Powerful AI technology
- Patent DNA Extraction
Browse by: Latest US Patents, China's latest patents, Technical Efficacy Thesaurus, Application Domain, Technology Topic, Popular Technical Reports.
© 2024 PatSnap. All rights reserved.Legal|Privacy policy|Modern Slavery Act Transparency Statement|Sitemap|About US| Contact US: help@patsnap.com