Image orthogonal moment numerical stability analyzing method
An analysis method and stability technology, which is applied in the field of numerical stability analysis of image orthogonal moments, can solve problems such as limiting the application of orthogonal moments, troublesome technical personnel, etc.
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Embodiment 1
[0055] This embodiment discloses a method for analyzing the numerical stability of image orthogonal moments, including the following steps:
[0056] (1) Analyze the reasons for the instability of the three-term recursive formula of the orthogonal polynomial;
[0057] The three-term recursive formula is as follows:
[0058] P k (x)=A k (x)P k-1 (x)-B K (x)P k-2 (x)=(α k x-ω k )P k-1 (x)-γ k P k-2 (x) (1-1)
[0059] Among them, P k (x),P k-1 (x) and P k-2 (x) are nth order, n-1th order and n-2th order discrete orthogonal polynomials respectively, A k (x) and B k (x) is the iteration coefficient.
[0060] In the actual computer operation process, the truncation error occurs due to the determination of the number of digits in the system, which makes the observed value deviate from the actual value. This truncation error varies throughout the recursion, potentially affecting the confidence in our observed expected value. Therefore, it is necessary to analyze the n...
Embodiment 2
[0118] This embodiment discusses the instability analysis in the recursive calculation of continuous orthogonal Legendre polynomials, discrete orthogonal Tchebichef polynomials and discrete orthogonal Krawtchouk polynomials.
[0119] (1) Stability analysis of Legendre polynomial recursive calculation:
[0120] The three-term recursive formula for the Legendre polynomial:
[0121]
[0122] According to the first instability theorem, redefine the variable y 1 (k)=L(k),y 2 (k)=L(k+1), then formula (1-15) can be written as:
[0123] Y(k)=(y 2 (k),y 1 (k)) T =G(k)Y(k-1) (2-2)
[0124] and
[0125] For Legendre polynomials there is A x (k)=(2k-1)x / k and B(k)=(k-1) / k,
[0126] Suppose the element q of the asymptotically positive definite matrix Q 11 (k)>0,q 12 (k)≤0 and q 22 (k)>0 and considering that it has a solution P, formula (13) can be expressed as:
[0127]
[0128] If you specify q 11 (k)=μ>0,q 22 (k)=ν>0,q 12 (k)=q 21 (k)=0 and the symmetric matrix P...
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