CIC filter design method based on parallel computation
A filter design, filter technology, applied in impedance networks, digital technology networks, electrical components, etc., can solve problems such as processing speed limitations, and achieve the effect of ensuring system operation
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[0067] Example 1
[0068] In Embodiment 1, the operation results of a single-stage parallel CIC filter and a traditional single-stage serial CIC filter are compared.
[0069] Suppose the sampling frequency of the input signal is f s = 1GHz. The operating frequency of the traditional single-stage serial CIC needs to be at f s =1GHz. In the parallel CIC design of the present invention, M=4, D=8, and a single-stage CIC filter is equivalent to Q=1. The parallel filter works at f cic = F s / M=250MHz.
[0070] The design of the single-stage parallel CIC filter in Embodiment 1 includes the following steps:
[0071] ①For the sampling rate f s =1GHz input signal S i ,0≤i≤N (where N is the fixed data length). We design the filter working frequency as f cic =250MHz, the number of parallels is M=4. Determine the number of samples D=8;
[0072] ② Divide it into groups of 4 data, and divide the signal flow S i ,0≤i≤N becomes the following formula:
[0073] {(S 0 ,S 1 ,...,S 3 ),(S 4 ,S 5 ,...,S...
Example Embodiment
[0084] Example 2
[0085] In Embodiment 2, the operation results of the multi-stage parallel CIC filter and the traditional multi-stage serial CIC filter are compared.
[0086] Suppose the sampling frequency of the input signal is f s = 1GHz. The operating frequency of the traditional single-stage serial CIC needs to be at f s =1GHz. In the parallel CIC design of the present invention, M=4, D=8, and a single-stage CIC filter is equivalent to Q=1. The parallel filter works at f cic = F s / M=250MHz.
[0087] The design of the multi-stage parallel CIC filter in Embodiment 2 includes the following steps:
[0088] ①For the sampling rate f s =1GHz input signal S i ,0≤i≤N (where N is the fixed data length). We design the filter working frequency as f cic =250MHz, the number of parallels is M=4. Determine the number of samples D=8;
[0089] ② Divide it into groups of 4 data, and divide the signal flow S i ,0≤i≤N becomes the following formula:
[0090] {(S 0 ,S 1 ,...,S 3 ),(S 4 ,S 5 ,...,...
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