Antisymmetric involute plastic gear
A technology of plastic gears and involutes, applied in belt/chain/gear, components with teeth, portable lifting devices, etc. Long wear life, good elasticity, low noise effect
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Embodiment approach 1
[0014] The tooth shape of the gear is a large pressure angle involute tooth profile 4 generated by the dedendum circle 1 and a small diameter base circle 2, a small pressure angle involute tooth profile 6 generated by a large diameter base circle 3, an addendum 5 and a transition Composed of curve 7.
[0015] for alpha 1 >α 2 Time:
[0016] by alpha 1 =15°, α 2 =14.5°, m=1.25, z=24, h a1 * = 1.0, h a2 * =0.95, c 1 * =0.35, c 2 * =0.4, m a = 0.4 / 24 = 0.0167.
[0017] got d b1 =mzcosα 1 =1.25×24cos15°=28.98(mm)
[0018] d b2 =mzcosα 2 =1.25×24cos14.5°=29.04(mm)
[0019] d a =(z+2h a1 * )m=(24+2×1)×1.25=32.5(mm)
[0020] S a = d b1 m a =28.98×0.0167=0.483966(mm)
[0021] d f =(z-2h a1 * -2c 1 * )m=(24-2×1-2×0.35)×1.25=26.625(mm)
[0022] According to the base circle diameter d b1 and d b2 For the same reference and opposite directions, the involute tooth profile 4 with a large pressure angle and the involute tooth profile 6 with a small pressure...
Embodiment approach 2
[0024] for alpha 1 >α 2 Time:
[0025] by alpha 1 =30°, α 2 =14.5°, m=1.25, z=24, h a1 * = 1.0, h a2 * =0.90, c1 * =0.3, c 2 * =0.4, m a =0.325 / 24=0.0135.
[0026] got d b1 =mzcosα 1 =1.25×24cos30°=25.98(mm)
[0027] d b2 =mzcosα 2 =1.25×24cos14.5°=29.04(mm)
[0028] d a =(z+2h a1 * )m=(24+2×1)×1.25=32.5(mm)
[0029] S a = d b1 m a =25.98×0.0135=0.35073(mm)
[0030] d f =(z-2h a1 * -2c 1 * )m=(24-2×1-2×0.3)×1.25=26.75(mm)
[0031] Diameter d at tooth top 5 a The arc length between the two involutes is 2.3364mm. Since the diameter d of the dedendum circle 1 f greater than the diameter d of the small diameter base circle 2 b1 , so the formed large pressure angle involute tooth profile 4 is completely involute; due to the diameter d of the dedendum circle 1 f smaller than the diameter d of the large diameter base circle 3 b2 , so the small pressure angle involute tooth profile 6 formed is divided into two parts: the involute between the large d...
Embodiment approach 3
[0033] for alpha 1 >α 2 Time:
[0034] by alpha 1 = 45°, α 2 =14.5°, m=1.25, z=24, h a1 * = 1.0, h a2 * = 1.0, c 1 * =0.45, c 2 * =0.45, m a =0.25 / 24=0.0104.
[0035] got d b1 =mzcosα 1 =1.25×24cos45°=21.21(mm)
[0036] d b2 =mzcosα 2 =1.25×24cos14.5°=29.04(mm)
[0037] d a =(z+2ha1 * )m=(24+2×1)×1.25=32.5(mm)
[0038] S a = d b1 m a =21.21×0.0104=0.220584(mm)
[0039] d f =(z-2h a1 * -2c 1 * )m=(24-2×1-2×0.45)×1.25=26.375(mm)
[0040] Diameter d at tooth top 5 a The arc length between the two involutes is 5.4899mm. Since the diameter d of the dedendum circle 1 f greater than the diameter d of the small diameter base circle 2 b1 , so the formed large pressure angle involute tooth profile 4 is completely involute; due to the diameter d of the dedendum circle 1 f smaller than the diameter d of the large diameter base circle 3 b2 , so the small pressure angle involute tooth profile 6 formed is divided into two parts: the involute between the la...
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