Method for judging irradiation of product and dosage thereof
A product, irradiation technology, used in dosimeters, measuring devices, material analysis using wave/particle radiation, etc., can solve the problems of undetermined radiation dose, false positives, false negatives, etc., to reduce false negative results. Probability, accurate and rapid judgment, and the effect of improving detection sensitivity
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example 1
[0058] Example 1: Beet sample irradiation and dose determination:
[0059] Select five batches of unirradiated sugar beet samples in advance according to the method of the first step above, each batch is divided into two parts, and one part of each batch is taken for a total of 5 parts for detection, and it is obtained: log(DEFT 0-1 ) = 6.48, log(APC 0-1 ) = 7.08, D C0-1 =log(DEFT 0-1 )-log(APC 0-1 )=-0.6,...,D C0-2 =-0.49,D C0-3 =-0.71,D C0-4 =-0.55,D C0-5 = -0.65, calculate
[0060] The other five samples in the five batches passed the sugar beet irradiation dose (ranging from 0 to 0.8kGy, 0.8>2×0.28) survival test, respectively: D 10-1 =0.24kGy,D 10-2 = 0.34kGy, D 10-3 =0.26kGy,D 10-4 = 0.30kGy, D 10-5 = 0.26kGy, calculate
[0061] 1) Beet sample 1 under inspection:
[0062] DEFT / APC method test results: log(DEFT)=6.29, log(APC)=4.32, Dc=1.97, because According to criterion 1, the sample has been treated with a dose greater than 0.28 / 2 = 0.14 kGy. ...
example 2
[0067] Example 2: Irradiation of yellow line fish samples and its dose determination:
[0068] Select five batches of unirradiated yellow-haired fish samples in advance according to the method of the first step above, each batch is divided into two parts, and one part of each batch is taken for a total of 5 parts for detection, and it is obtained: log(DEFT 0-1 ) = 10.65, log(APC 0-1 ) = 8.34, D C0-1 =log(DEFT 0-1 )-log(APC 0-1 )=2.31,...,D C0-2 =2.2,D C0-3 =2.40,D C0-4 =2.32,D C0-5 = 2.32, calculate
[0069] The other five samples in the five batches passed the survival test of yellow line fish irradiation dose (ranging from 0 to 4.0 kGy, 4.0>2×1.42), respectively: D 10-1 = 1.42kGy, D 10-2 = 1.30kGy, D 10-3 = 1.46kGy, D 10-4 = 1.44kGy, D 10-5 = 1.48kGy, calculate
[0070] 1) Sample 1 of the inspected yellow line fish:
[0071] DEFT / APC method test results: log(DEFT)=10.45, log(APC)=6.84, Dc=3.61, because According to criterion 2, it cannot be judged w...
example 3
[0076] Example 3: Irradiation and dose determination of black pepper samples:
[0077] Select five batches of unirradiated black pepper samples in advance according to the method of the first step above, each batch is divided into two parts, and one part of each batch is taken for a total of 5 parts for testing, and it is obtained: log(DEFT 0-1 ) = 6.92, log(APC 0-1 ) = 5.77, D C0-1 =log(DEFT 0-1 )-log(APC 0-1 )=1.15,...,D C0-2 =1.18,D C0-3 =1.20,D C0-4 =1.08,D C0-5 = 1.14, calculate
[0078] Another five samples in the five batches passed the black pepper class irradiation dose (range is 0~6.0kGy, 6.0>2×2.39) survival test, respectively: D 10-1 =2.39kGy,D 10-2 =2.44kGy,D 10-3 =2.22kGy,D 10-4 =2.31kGy, D 10-5 = 2.59kGy, calculate
[0079] 1) Detected black pepper sample 1
[0080] DEFT / APC test results: log(DEFT)=6.9, log(APC)=4.41, Dc=2.49, because According to criterion 3, it cannot be judged whether the sample has been treated with a dose > 2.0 kGy. ...
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