A Power System Phasor Calculation Method Applicable to Frequency Offset
A technology of power system and calculation method, which is applied in the direction of frequency measurement device, measurement of electrical variables, frequency to amplitude conversion, etc., can solve the problems of large amount of calculation, troublesome correction, sacrifice of measurement accuracy, etc., achieve small memory occupation, simple method, The effect of fast calculation speed
- Summary
- Abstract
- Description
- Claims
- Application Information
AI Technical Summary
Problems solved by technology
Method used
Image
Examples
Embodiment 1
[0050] Assume that the sequence of single-phase sampled values after low-pass filtering is expressed as X(i)=1.34*cos(2*f*π*i*0.00025), i=0, 1, 2, 3, . . . . N is taken as 80, that is, 80 sampling points per cycle, and the sampling interval is T S =0.00025 seconds. Unless otherwise specified, the calculation variable is of double type, the unit of phase is angle, the unit of frequency is Hz, and decimal truncation is rounded off.
[0051] Assume that the current system is in a three-phase balanced state, the system frequency is 47Hz, and the current sampling time is (100×T S ), then when f=47Hz, the nearest integral frequency range to this frequency is: M=85, 47Hz is out of the whole point frequency range. According to the algorithm rules, choose step three.
[0052] X(i) A =1.34*cos(2*f*π*i*0.00025)
[0053] X ( i ) B = 1.34 * cos ...
Embodiment 2
[0059] Assume that the sequence of single-phase sampled values after low-pass filtering is expressed as X(i)=1.34*cos(2*f*π*i*0.00025), i=0, 1, 2, 3, . . . . N is taken as 80, that is, 80 sampling points per cycle, and the sampling interval is T S =0.00025 seconds. Unless otherwise specified, the calculation variable is of double type, the unit of phase is angle, the unit of frequency is Hz, and decimal truncation is rounded off.
[0060] Assuming that the current system is in a three-phase unbalanced state, there is a 5% negative sequence component, and the negative sequence leads the positive sequence by 30°. The system frequency is 47Hz, and the current sampling moment is (100×T S ).
[0061] Then when f=47Hz, the whole point frequency range closest to this frequency is: M=85, 47Hz is out of the whole point frequency range. According to the algorithm rules, choose step five.
[0062] X ( i ) ...
Embodiment 3
[0070] Assume that the sequence of single-phase sampled values after low-pass filtering is expressed as X(i)=1.34*cos(2*f*π*i*0.00025), i=0, 1, 2, 3, . . . . N is taken as 80, that is, 80 sampling points per cycle, and the sampling interval is T S =0.00025 seconds. Unless otherwise specified, the calculation variable is of double type, the unit of phase is angle, the unit of frequency is Hz, and decimal truncation is rounded off.
[0071] Suppose the current system frequency is 50.01Hz, and the sampling time is (100×T S ), then when f=50.01Hz, according to the algorithm rules, choose step 2. Select the sampling window length as the default power frequency sampling points per cycle N=80.
[0072] X 100 = 2 80 Σ k = - 79 0 x 100 + ...
PUM
Login to View More Abstract
Description
Claims
Application Information
Login to View More 