Under-sampling waveform frequency estimation method and device under strong noise interference
A technology of frequency estimation and sampling frequency, applied in the field of frequency estimation of under-sampled waveforms, it can solve the problems of large error, deviation, and unsuitable frequency estimation of reconstruction results, and achieve strong adaptability, high accuracy, and improve anti-noise performance. Effect
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Embodiment 1
[0056] A frequency estimation method for undersampled waveforms under strong noise interference, see figure 1 , the frequency estimation method includes the following steps:
[0057] 101: respectively with f s1 ~ f sL For the sampling rate, L channels of low-speed sampling are performed on high-frequency signals containing noise interference to obtain L channels of sampling signals x i (n)(i=1,...,L);
[0058] 102: L channels of signal x obtained by sampling at a low rate i (n) Perform Fast Fourier Transform (FFT), and obtain f for each channel si (1≤i≤L) sample points and store them;
[0059] 103: Use the L-channel FFT spectrum distribution characteristics to extract the frequency corresponding to the peak position of the amplitude spectrum as the noise-containing remainder of each channel output, and set the residual error of each channel to be Δr i , that is Among them, r i is the signal frequency f 0 Modulo each sampling rate f si remainder obtained after.
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Embodiment 2
[0066] Below in conjunction with specific calculation formula, example the scheme in embodiment 1 is described in detail:
[0067] 201: L-channel low-speed undersampling;
[0068] Let the received noisy signal be x(t)=aexp(j2πf 0 t)+ω(t), f 0 is the signal frequency, that is, the measured frequency. Perform L-way undersampling on it, and the sampling frequency is f s1 ~ f sL , sampling frequency f si (1≤i≤L) requires that the common divisor is M, and f si The factor Γ obtained after dividing by the common divisor M i It is pairwise prime. Then each sampling signal x i (n) is:
[0069]
[0070] 202: Perform FFT transformation on each channel of the sampled signal, analyze the spectrum characteristics, and extract the remainder;
[0071] For the L signal x obtained after sampling i (n), respectively do the sampling frequency f si Point FFT transformation, and obtain the magnitude spectrum of the i-th path, find out the frequency value corresponding to the largest ...
Embodiment 3
[0094] Below in conjunction with concrete experimental data, accompanying drawing, the scheme in embodiment 1 and 2 is carried out feasibility verification, see the following description for details:
[0095] Analysis of results
[0096] Experiment 1 screening error remainder
[0097] It may be advisable to take L=6 channels of undersampling and K=4 channels with small error residuals as an example to illustrate the detailed process of screening error residuals. Assume that there is a large error in the remainder of the second path, that is, the error Δr 2 >M / 4, and set the sampling frequency as f s1 =18M,f s2 =19M,f s3 =23M,f s4 =25M,f s5 =29M,f s6 =31M, where M=801 is f s1 ~ f s6 greatest common divisor of . The signal frequency is set to f 0 =N=250000Hz.
[0098] According to the closed CRT algorithm of literature [10], the correct remainder set is r={48946496105019700177101690}, and the correct folded integer n i The set is n={171613121010}, and the set of err...
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