High-safety lithium ion battery
A lithium-ion battery, safety performance technology, applied in battery electrodes, secondary batteries, circuits, etc., can solve complex problems
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[0023] According to the lithium ion secondary battery provided by the present invention, the main steps of the preparation method of the battery are well known to those skilled in the art. Generally speaking, the preparation method of the battery includes placing the electrode assembly in the battery case and adding electrolyte, Then, it was sealed to obtain a lithium ion secondary battery. Among them, the sealing method and the amount of electrolyte are well known to those skilled in the art.
[0024] Just pay attention to the use of polymer positive temperature coefficient thermal sensitive materials when the conductive agent is added to the positive electrode slurry and / or the negative electrode slurry.
Example Embodiment
[0025] Example 1
[0026] The positive electrode active material is LiCoO2, and the binder is PVDF. Dissolve PVDF in solvent NMP to prepare PVDF solution, put the positive electrode active material and conductive polymer material as a conductive agent into the solvent, mix well to make positive electrode slurry, its composition is LiCoO2: PVDF: polymer Conductive agent=100:8:6.89. The prepared positive electrode slurry is coated and sliced.
[0027] The negative electrode active material uses graphite, and the binder uses CMC and SBR. Dissolve CMC in water to prepare a CMC solution, add graphite into the solvent, mix well, and then add SBR emulsion to make a slurry, which is composed of graphite: CMC: SBR: polymer conductive agent = 100: 1.5: 2.5:3.22. The prepared negative electrode slurry is coated and sliced.
[0028] Use the above-prepared positive electrode sheet, negative electrode sheet, and separator to wind the pole core of a lithium ion square battery, put the pole cor...
Example Embodiment
[0029] Example 2
[0030] The composition of the positive electrode slurry in Example 1 was changed to LiCoO2:PVDF: polymer conductive agent=100:8:4.5.
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