A method and system for obtaining primary large current under low actual load

Abstract

The invention discloses a method for obtaining a large current under low actual load, which includes the following steps: S1: use any phase of the three-phase lines of the high-voltage system as an input line, and set a test line on the input line; The test line includes a series-connected current booster and the electrical equipment to be tested; S2: set the primary side of the current booster on the input line, and connect the secondary side of the current booster to the electrical equipment to be tested in series; S3: connect the The end of the electrical equipment under test away from the secondary side of the current booster is connected to the input line. The invention also discloses a system for obtaining primary large current under low actual load. The present invention realizes high current through the current booster, and realizes high voltage through direct connection to the input line, so that the electrical equipment to be tested can be placed in the environment to be tested with high current and high voltage under the condition that the load of the input line is small , effectively reducing the investment cost and test cost.

Description

technical field [0001] The invention relates to the field of electrical engineering, in particular to a method and system for obtaining a large primary current under a low actual load. Background technique [0002] The real operating performance of a large number of electrical equipment can only be accurately measured under the conditions of simulating its actual operating conditions. In the power transmission and distribution system, the primary electrical equipment is in the operating state of high voltage and high current. Therefore, to simulate the operating conditions of electrical equipment, the electrical equipment must be placed in high-voltage, high-current operating conditions. According to the relationship formula P=UIcosФ between power and current, it can be seen that when the voltage is constant, the size of the primary current is determined by the load power. To generate a larger primary current, a larger load power is required. Taking a 10kV system as an exam...

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Problems solved by technology

Taking a 10kV system as an example, if a primary current of 200A is to be generated and the power factor is calculated as 1.0, the power required for a single phase is P=10kV*200A*1.0=2000kVA, and the power required for a three-phase is about 3500kVA. The load power is very large, correspondingly, the capacity of the required transformer is also large, which will greatly increase the investment cost of the test equipment, and this test method requires a high power supply capacity, which is not available in general laboratories. At the same time, this also causes the cost of the test to be too large. Taking the cost of electricity as an example, if the calculation is based on 0.5 yuan per kilowatt-hour, the power consumption per hour of the single-phase test is 2000 kilowatt-hours, and the electricity fee per hour is 1000 yuan; in the case of three-phase The hourly electricity bill exceeds 1700 yuan

[0003] In the prior art, when carrying out a simulation test of electrical equipment, high voltage and high current operating conditions are required, which greatly increases the investment cost and test cost of test equipment, and also has high requirements for power supply capacity

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