Method for producing raw material for sulfur-based compound fertilizer from waste phosphoric acid
A technology of sulfur-based compound fertilizer and waste phosphoric acid, applied in the application, fertilization device, fertilizer mixture and other directions, can solve the problems of high recycling cost, waste of phosphorus-containing resources, difficult treatment, etc. Absorbent, easy-to-absorb effect
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example 1
[0040] Select No. 1 waste phosphoric acid and No. 1 phosphate rock powder for reaction treatment, and the specific calculation is as follows:
[0041] 1. Select 10kg of phosphoric acid, according to the detection value H 2 SO 4 =4.88%, then the content of sulfuric acid in waste phosphoric acid is:
[0042] 10*4.88%=0.488Kg
[0043] Select 1Kg phosphate rock powder, the required amount of sulfuric acid M is:
[0044] S1=(CaO)×98 / 56=1×41.24%×98÷56=0.7217Kg
[0045] S2=(MgO)×98 / 40=1×2.73%×98÷40=0.0669Kg
[0046] S3=(Al 2 o 3 )×98 / 102=1×2.22%×98÷102=0.0213Kg
[0047] M=S1+S2+S3=0.7217Kg+0.0669Kg+0.0213Kg=0.8099Kg
[0048] The phosphate rock powder that needs to be added to 10kg of waste phosphoric acid is selected as:
[0049] 0.488Kg÷0.8099Kg=0.60Kg
[0050] 2. The produced phosphoric acid P 2 o 5 The content is:
[0051] The conversion rate is 97.5%, the washing rate is 99%, and the mechanical loss is 3%:
[0052] 0.60Kg×27.12%×97.5%×99%×(100-3)%=0.1524Kg
[0053]...
example 2
[0056] Select No. 1 waste phosphoric acid and No. 2 phosphate rock powder for reaction treatment, and the specific calculation is as follows:
[0057] 1. Select 10kg of phosphoric acid, according to the detection value H 2 SO 4 =4.88%, then the content of sulfuric acid in waste phosphoric acid is:
[0058] 10×4.88%=0.488Kg
[0059] Select 1Kg phosphate rock powder, the required amount of sulfuric acid M is:
[0060] S1=(CaO)×98 / 56=1×45.9%×98÷56=0.8033Kg
[0061] S2=(MgO)×98 / 40=1×2.64%×98÷40=0.0647Kg
[0062] S3=(Al 2 o 3 )×98 / 102=1×0.95%×98÷102=0.0091Kg
[0063] M=S1+S2+S3=0.8033Kg+0.0647Kg+0.0091Kg=0.877Kg
[0064] The phosphate rock powder that needs to be added to 10kg of waste phosphoric acid is selected as:
[0065] 0.488Kg÷0.877Kg=0.556Kg
[0066] 2. The produced phosphoric acid P 2 o 5 The content is:
[0067] The conversion rate is 97.5%, the washing rate is 99%, and the mechanical loss is 3%:
[0068] 0.556Kg×29.81%×97.5%×99%×(100-3)%=0.1551Kg
[0069] ...
example 3
[0072] Select No. 1 waste phosphoric acid and No. 3 phosphate rock powder for reaction treatment, and the specific calculation is as follows:
[0073] 1. Select 10kg of phosphoric acid, according to the detection value H 2 SO 4 =4.88%, then the content of sulfuric acid in waste phosphoric acid is:
[0074] 10*4.88%=0.488Kg
[0075] Select 1Kg phosphate rock powder, the required amount of sulfuric acid M is:
[0076] S1=(CaO)×98 / 56=1×46.02%×98÷56=0.8054Kg
[0077] S2=(MgO)×98 / 40=1×1.25%×98÷40=0.0306Kg
[0078] S3=(Al 2 o 3 )×98 / 102=1×1.42%×98÷102=0.0136Kg
[0079] M=S1+S2+S3=0.8054Kg+0.0306Kg+0.0136Kg=0.8496Kg
[0080] The phosphate rock powder that needs to be added to 10kg of waste phosphoric acid is selected as:
[0081] 0.488Kg÷0.8496Kg=0.574Kg
[0082] 2. The produced phosphoric acid P 2 o 5 The content is:
[0083] The conversion rate is 97.5%, the washing rate is 99%, and the mechanical loss is 3%:
[0084] 0.574Kg×32.11%×97.5%×99%×(100-3)%=0.1726Kg
[008...
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