Method for obtaining force and torque and doing work on load as well as device and application of method
A technology of torque and work, applied in the field of new energy, can solve problems that have not been practically applied
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Embodiment 1
[0047] Embodiment 1; device A, fluid is air, tractor is motor, and load is generator; Motor, device, generator are fixedly connected in series with coaxial successively, wherein the rated output power of generator is greater than the rated input power of motor, neglecting friction Energy loss caused by sassafras, etc.
[0048] The working process is that the excitation circuit of the generator is opened, the motor is started, the drive device and the rotor of the generator rotate, and the excitation circuit of the generator is closed after the speed reaches the rated value, the generator works and outputs power;
[0049] To illustrate further with an example calculation,
[0050] Suppose, motor power P=10kw, speed n=3000rpm, torque T 0 =P / ω=10000 / 2 / π / 3000×60=32N.m, ω is the angular velocity, the radius of gyration of the end hole outside the cavity r 1 =0.3m, radius of gyration of inner hole r 2 =0.05m, 4 cavities are symmetrically distributed, each airfoil area s=0.3m×0.1m...
Embodiment 2
[0052] Embodiment 2; Apparatus B, fluid is air, and four cavity bodies revolve in the closed body, and device is connected with generator coaxially, suppose; The power P of the air extraction equipment on the closed body 1 =2.2Kw, air volume Q=18000m3 / h, this kind of fan is a very common fan in the market, the generator speed is 3000 rpm, the radius of rotation of the end hole outside the cavity is r=1m, and the four cavity bodies are symmetrically distributed. The area of each airfoil s=0.3m×0.1m=0.03m 2 , the thrust arm of the airfoil part is L=0.8m, the lift coefficient of the airfoil part is c=0.8, and the area of the outer end hole of each cavity is S 1 =0.3m×0.1m=0.03m 2 , the following ignores the energy loss caused by friction, etc., and the calculation results are rounded up;
[0053] Calculation; the sum of the area of the outer end holes of the four cavities S 2 =0.03×4=0.12m 2 , the air flow velocity V=Q / S in the inner cavity of the cavity and the outer e...
Embodiment 3
[0054] Embodiment 3: Device A is connected with the main shaft of the machine tool, the output shaft of the internal combustion engine, the input and output shafts of the gearbox, and the motor of the air conditioner compressor in series connection or multi-axis connection, and transmits increased torque, and the output power is greater than the input power.
[0055] Take the machine tool as an example to illustrate the calculation; the machine tool is a vertical machining center, and the spindle power is P 0 =15Kw, the spindle speed is n=10000rpm, the spindle motor torque is 15.N.m at this speed, the device is fixed and connected in series with the machine tool spindle coaxially, the size of the device; r 1 = 0.15m, r 2 =0.03m, 4 cavities, the area of each airfoil is s=0.2m×0.1m=0.02m 2 , the moment arm of the airfoil part is L=0.1m, the lift coefficient of the airfoil part is 0.8, and the influence of resistance such as frictional force is ignored, and the calculated resu...
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