Portable multifunctional biological impactor and method for obtaining impact energy based on the impactor
A multi-functional and portable technology, applied in the testing of machines/structural components, measuring devices, impact testing, etc., can solve the problems of inability to realize portability, single function, complex structure, etc., and achieve light weight, fast response and simple structure Effect
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Embodiment 1
[0062] When injecting methane into cylinder 1:
[0063] methane burning CH 4 +2O 2 =2H 2 O (gaseous) + CO 2
[0064] According to the constant volume-adiabatic equation, from the formula (5), there are:
[0065] h P +P R V=H R +P R V
[0066] h P =H R +(V P -V R ) P=H R +(n P -n R ) R m T
[0067] no P and n R is the kilomoles of gaseous substance, R m is the universal gaseous constant.
[0068] When H 2 When O exists in gaseous state, n R =n P , then H P =H R .
[0069] The chemical equation for the combustion of methane is:
[0070] h R =(H CH4 ) 298 =(h 0 f )CH 4
[0071] Looking up the table, the enthalpy of formation of methane is
[0072] (h 0 f )CH 4 =-75850kJ / kmol
[0073] Then the enthalpy of the reactants is
[0074] h R =-75850kJ / kmol
[0075] According to the chemical reaction equation:
[0076] h P =2(h 0 f +△h) H2O +(h 0 f +△h) CO2 (a)
[0077] Check the table to get CO 2 and H 2 The enthalpy of formation o...
Embodiment 2
[0099] When injecting propane into cylinder 1:
[0100] Propane burning C3 h 8 +5O 2 =4H 2 O (gaseous) +3CO 2
[0101] According to the constant volume-adiabatic equation, from the formula (5), there are:
[0102] h P +P R V=H R +P R V
[0103] h P =H R +(V P -V R ) P=H R +(n P -n R ) R m T
[0104] no P and n R is the kilomoles of gaseous substance, R m It is the universal gas state constant, 8.37kJ / kmol.K.
[0105] When H 2 When O exists in gaseous state, 1+n R =n P , then H P =R m T+H R .
[0106] Looking up the table, the enthalpy of formation of propane is
[0107] (h 0 f )C 3 h 8 =-104000kJ / kmol
[0108] Then the enthalpy of the reactants is
[0109] h R =R m T-104000=8.37×293-104000=-101506kJ / kmol
[0110] According to the chemical reaction equation:
[0111] h P =4(h 0 f +△h) H2O +3 (h 0 f +△h) CO2 (b)
[0112] Check the table to get CO 2 and H 2 The enthalpy of formation of O is:
[0113] (h 0 f ) H2O =-393520kJ / ...
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