Lactam derivative and application thereof
A compound, halogen technology, applied in the field of medicine, can solve problems such as QT interval prolongation
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Embodiment 1
[0094] Example 1, 7-(4-(4-(6-fluorobenzo[d]isoxazol-3-yl)piperidinyl-1-yl)butoxy)-2-methyl-3,4 -Dihydroisoquinolin-1(2H)-one (1)
[0095](1) 4-Methoxyphenethylamine (0.1mol) was dissolved in 300ml of dichloromethane, cooled to 0°C in an ice bath, 20ml of triethylamine was added, and ethyl chloroformate (0.15mmol) was slowly added dropwise thereto , After adding, react at room temperature for 12h. After the reaction was completed, the reaction solution was washed with water and 10% dilute hydrochloric acid solution, the organic layer was dried with anhydrous magnesium sulfate, the solvent was evaporated under reduced pressure, and the residue was washed with petroleum ether. After drying, 20.3 g of a yellow oil was obtained, with a yield of 91 %, MS (ESI) m / z 223.3 ([M+H] + ).
[0096] (2) Dissolve 0.2 mol of phosphorus pentoxide in 200 ml of methanesulfonic acid, add 0.1 mol of the yellow oil prepared in the first step into it in batches, react at 140 ° C, and after the rea...
Embodiment 2
[0103] Example 2, 7-(4-(4-(2-methoxyphenyl)piperazin-1-yl)butoxy)-2-methyl-3,4-dihydroisoquinoline-1( 2H)-ketone (2)
[0104] Using 1-(2-methoxyphenyl)piperazine instead of 6-fluoro-3-(piperidinyl-4-yl)benzo[d]isoxazole as raw material, the target compound was prepared according to the method of Example 1 , and the structural formula is shown in number (2) in Table 1. 1 H-NMR (600MHz, CDCl 3 )δ1.72-1.86(m,4H),2.50(t,2H,J=12Hz),2.69-2.70(m,3H),2.94(t,2H,J=12Hz),3.12-3.16(m,2H ),3.18(s,3H),3.54(t,2H,J=12Hz),3.87(s,3H),4.05(t,2H,J=6Hz),6.86-6.88(m,1H),6.91-7.07 (m, 5H), 7.61 (d, 1H, J=6Hz). MS (ESI) m / z 424.3 ([M+H] + ).
Embodiment 3
[0105] Example 3, 2-methyl-7-(4-(4-(3-(trifluoromethyl)phenyl)piperazin-1-yl)butoxy)-3,4-dihydroisoquinoline -1(2H)-one(3)
[0106] Use 1-(3-(trifluoromethyl)phenyl) instead of 6-fluoro-3-(piperidinyl-4-yl)benzo[d]isoxazole as raw material, and prepare the target according to the method of Example 1 Compound, structural formula as shown in number (3) in Table 1. 1 H-NMR (600MHz, CDCl 3 )δ1.73-1.88(m, 4H), 2.21-2.22(m, 2H), 2.50(t, 2H, J=12Hz), 2.64-2.66(m, 3H), 2.94(t, 2H, J=12Hz ),3.18(s,3H),3.26-3.28(m,3H),3.55(t,2H,J=12Hz),4.06(t,2H,J=6Hz),6.96-6.98(m,1H),7.06 -7.10(m,3H),7.12-7.14(m,1H),7.34-7.36(m,1H),7.61(d,1H,J=6Hz). MS(ESI) m / z 462.2([M+H ] + ).
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