Spectrophotometric method for quantifying total lipid content and application thereof
A spectrophotometry, lipid content technology, applied in the field of instrument analysis, can solve the problems of lack of colorimetric reagents, immaturity, inaccurate colorimetric results, etc., to achieve accurate analysis results, overcome bottlenecks, and avoid solvent interference.
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Embodiment 1
[0016] One of the establishment of linear relationship: use petroleum ether at 60-90°C as solvent, prepare tetra-sec-octyloxyphthalocyanine nickel solution by weighing, dissolving and diluting, the concentration is 1.2×10 -5 mol L -1 . Prepare a series of solutions of peanut oil 1:0, 1:1, 1:3, 1:7, 1:15, 1:31, 1:63 (V 花生油 :V 石油醚 ), the corresponding mass volume concentrations are 0.9216, 0.4608, 0.2304, 0.1152, 0.0576, 0.0288, 0.0144g·mL -1 . The volume of the detection solution in the cuvette is constant at 3mL. Use a pipette to add 2.5mL of the above-mentioned phthalocyanine solution to the cuvette, then add 0.5mL of petroleum ether, and cover the cuvette mouth with a small piece of plastic wrap. Press the mouth of the dish with the thumb, and press the bottom of the dish with the index finger, and vibrate 3 times, as a test reference sample. Using a pipette, add 2.5mL of the above-mentioned phthalocyanine solution to the cuvette, then add 0.5mL of the peanut oil soluti...
Embodiment 2
[0019] The second establishment of linear relationship: operate as in Example 1, if the concentration of the phthalocyanine solution is prepared as 2.4 × 10 - 5 mol L -1 , after mixing with the oil sample, its concentration in the test solution was diluted to 2.0×10 -5 mol L -1 , other operations are the same as in Example 1, and the result can be equation (4).
[0020] ΔA=4.92511c l +0.01478 (4)
Embodiment 3
[0022] The third establishment of linear relationship: operate as in Example 1, if the concentration of the phthalocyanine solution is prepared as 4.8 × 10 - 5 mol L -1 , after mixing with the oil sample, its concentration in the test solution was diluted to 4.0×10 -5 mol L -1 , other operations are the same as in Example 1, and the result can be equation (5).
[0023] ΔA=6.38683c l +0.02763 (5)
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