Tooth enamel composition, method for forming tooth enamel, and denture restoration
A composition and restoration technology, applied in the field of dental restoration, can solve the problems of limited use, high sintering temperature, adverse health effects, etc., and achieve the effects of improving quality, fast heating rate, and uniform glaze hanging
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Embodiment 1
[0063] Tooth enamel composition, comprising the following components in mass percentage:
[0064] 60.4% SiO 2 , 10% B 2 o 3 , 0.5% ZrO 2 , 9.0% Na 2 O, 7.0% K2 O, 1.4% Li 2 O, 2.3% CaO, 9.3% Al 2 o 3 .
[0065] Among them, Na 2 O and K 2 The molar ratio of O is 2.0;
[0066] K 2 O and Li 2 The molar ratio of O is 1.5;
[0067] Na 2 O, K 2 O and Li 2 The three total mass percentages of O are 17.5%;
[0068] SiO 2 and Al 2 o 3 The molar ratio of is 11.0;
[0069] SiO 2 The molar ratio to CaO is 24.2.
[0070] The preparation process is:
[0071] 1) Ingredients: Take Na according to the above ratio 2 CO 3 、K 2 CO 3 , ZrO 2 , Li 2 CO 3 , CaCO 3 , SiO 2 、Al 2 o 3 and B 2 o 3 to mix,
[0072] 2) Ball milling: Using the planetary ball milling process, put the mixture raw material obtained in step 1) into a polyurethane ball mill tank for ball milling. The corresponding ball milling parameters: speed 340 r / min, ball milling time 2h, solvent is alco...
Embodiment 2~14
[0082] The only difference between Examples 2-14 and Example 1 is that the component contents are different. As shown in Table 1, the preparation process and each parameter in the preparation process are the same as those of Example 1. N in Table 1 represents the molar weight, such as N (Na 2 O) stands for Na 2 The molar weight of O, the % in Table 1 represents the mass percent content.
Embodiment 15~18
[0084] The difference between Examples 15-18 and Example 1 lies in the preparation of the solvent in step 7) of the preparation process, and the rest are the same as in Example 1. The solvent data are shown in Table 2, and the % in Table 2 represents the mass percentage.
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