Rapid detection method and kit for indicating total glycoside content range of cistanche deserticola raw drug
A detection kit and detection method technology, which is applied in the field of biotechnology detection, can solve problems such as complexity, time-consuming, cumbersome experimental procedures, etc., and achieve the effects of strong specificity, high sensitivity, and shortened detection cycle
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Embodiment 1
[0085] Embodiment 1: Test the total glycoside content of Cistanche deserticola in random sampling (sample collection place: Inner Mongolia Left Banner).
[0086] (1) RNA extraction;
[0087] (2) RNA purification;
[0088] (3) reverse transcription reaction;
[0089] (4) RT-qPCR reaction;
[0090](5) Calculate the total glycoside content range according to the PCR results: According to the experiment, the CT values of the four genes are respectively: SEQ1 is 33.90369415, SEQ2 is 27.05919711, SEQ3 is 34.07738368, and SEQ4 is 30.52809588, and the calculated n 1 , n 2 , n 3 :
[0091] no 1 = 2 -(CT(SEQ1)-CT(SEQ4)) =0.096348214
[0092] no 2 = 2 -(CT(SEQ2)-CT(SEQ4)) =11.0724208
[0093] no 2 = 2 -(CT(SEQ3)-CT(SEQ4)) =0.085419674
[0094] Calculated according to formula (Ⅱ) to get P 1 ,P 2 ,P 2 , using the data in Table 5, in the left flag: N 11 =0.02,N 12 =1.63,N 13 =0.01,N 21 =0.01,N 22 =4.50,N 23 =0.04,N 21 = 0, N 32 =9.64,N 33 =0.01, compare 3 P at th...
Embodiment 2
[0100] Example 2: Test the total glycoside content of Cistanche deserticola in random samples (sample collection place: Right Banner, Inner Mongolia).
[0101] (1) RNA extraction;
[0102] (2) RNA purification;
[0103] (3) reverse transcription reaction;
[0104] (4) RT-qPCR reaction;
[0105] (5) Calculate the range of total glycoside content according to the PCR results: According to the experiment, the CT values of the four genes are respectively: SEQ1 is 32.59574763, SEQ2 is 28.58986219, SEQ3 is 34.18855667, and SEQ4 is 29.99904887, and the calculated n 1 , n 2 , n 3 :
[0106] no 1 = 2 -(CT(SEQ1)-CT(SEQ4)) =0.096348214
[0107] no 2 = 2 -(CT(SEQ2)-CT(SEQ4)) =11.0724208
[0108] no 2 = 2 -(CT(SEQ3)-CT(SEQ4)) =0.085419674
[0109] Calculated according to formula (Ⅱ) to get P 1 ,P 2 ,P 2 , using the data in Table 4, in the right flag: N 11 =0.04,N 12 =3.33,N 13 =0.38,N 21 =0.01,N 22 =8.02,N 23 =0.06,N 21 = 0, N 32 =21.33,N 33 =0.02, compare 3 P a...
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