Memory and writing method and reading method thereof
A memory and storage unit technology, applied in the storage field, can solve the problem that the memory is difficult to achieve high-density storage units, and achieve the effect of high-density storage
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Embodiment 1
[0062] Such as Figure 4As shown, the memory includes a plurality of memory cells, each of which includes a MOS transistor, three MTJs connected in series, a bit line, a word line, a source line, and a protector. For the specific connection relationship, see Figure 4 shown. Among them, the structure of each MTJ is the same, such as Figure 5 As shown, all of them include a fixed layer 201 , a barrier layer 202 and a free layer 203 stacked in sequence from bottom to top.
[0063] The thickness of the barrier layer of the three MTJs, the product of the resistance area, the write current density, the tunnel magnetoresistance ratio TMR and other parameters are all equal. The breakdown voltage of each MTJ is only related to the thickness and quality of the barrier layer MgO, so they are roughly equal.
[0064] Since the magnitude of the write current is proportional to the area of the MTJ, the magnitude of the write current corresponding to each MTJ can be well controlled by ...
Embodiment 2
[0083] The structure of the memory is the same as that of the memory in Embodiment 1, except that the memory has four storage states, and the resistances of the corresponding states are shown in Table 4.
[0084] Table 4
[0085]
[0086]
[0087] The memory read process see Figure 7 As shown, specifically, the reading process includes: first, judging whether the read resistance is greater than 24.5kOhm, when it is greater, the first bit (highest bit) is 0, and when it is less than, the first bit is 1;
[0088] When the first bit is 0, compare the read voltage with a second reference voltage, and the second reference voltage is greater than the first reference voltage, that is, select 32kOhm to compare with the read voltage, when the read voltage is greater than the second When the reference voltage is set, the second bit is 0, read 00, and when it is less than, read 01;
[0089] When the first bit is 1, compare the read voltage with a second reference voltage that is...
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