Preparation method of phenolic resin for heat insulating shield
A technology of phenolic resin and thermal insulation board, which is applied in the field of organic polymer compounds and refractory materials, can solve the problems of being not suitable for crushing into powdery resin, low strength of thermal insulation board, and low softening point of resin, achieving non-toxic and tasteless price, improving Bulk density and flexural strength, good performance effect
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Embodiment 1
[0025] Mix phenol and formaldehyde in a molar ratio of 1:0.9, add hydrochloric acid accounting for 1.5% by weight of phenol to the mixture, keep it at 80°C for 4 hours for addition polymerization, then add ethyl terephthalate accounting for 20% of phenol Glycol ester waste, stir evenly; Remove polycondensation by-product water through normal pressure distillation to 120 ℃; Distill the mixture under 0.02MPa, remove the unreacted phenol in the mixture to 0.3wt%, discharge the reaction product, Cool and grind.
Embodiment 2
[0027] Mix phenol and formaldehyde at a ratio of 1:0.75, add oxalic acid accounting for 3 wt% of phenol to the mixture, keep it at a constant temperature of 100°C for 5 hours for addition polymerization, add dimethyl terephthalate waste accounting for 30 wt% of phenol , stirring and mixing; through normal pressure distillation to 150 ° C to remove by-product water; distill the mixture at 0.05MPa, remove unreacted phenol in the mixture to 0.2wt%, discharge the reaction product, cool, and grind pink.
Embodiment 3
[0029] Mix phenol and formaldehyde at a ratio of 1:0.8, add 0.5wt% sulfuric acid accounting for phenol to the mixture, keep it at 90°C for 2 hours for addition polymerization, then add 40wt% butylene terephthalate Esters, stirred and mixed; distilled to 160°C under normal pressure; distilled the mixture at 0.04MPa to remove unreacted phenol in the mixture to 0.25%, discharge the reaction product, cool it, and grind it.
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