Current-magnitude-based open-circuit failure online-diagnosis method for power tube of inverter
A technology of open circuit fault and diagnosis method, which is applied in the direction of controlling electromechanical brakes, electrical components, controlling generators, etc., can solve problems such as poor robustness, and achieve good robustness
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specific Embodiment approach 1
[0035] Specific implementation mode one: the following combination Figure 1 to Figure 5 This embodiment is described. The current-based online diagnosis method for the open circuit fault of the inverter power tube is described in this embodiment. The permanent magnet synchronous motor drive system involved in the method includes a rectifier 1, a DC filter capacitor 2, and an inverter 3. , current sensor 4, permanent magnet synchronous motor 5, position sensor 6, controller 7 and isolation and drive circuit 8; as figure 1 shown;
[0036] Inverter 3 consists of power tube T 1 , T 2 ,...,T 6 Composed of, the phase A bridge arm is composed of T 1 and T 2 Constituted, the B-phase bridge arm is composed of T 3 and T4 Constituted, the C-phase bridge arm is composed of T 5 and T 6 pose, T 1 , T 3 and T 5 is the upper bridge arm, T 2 , T 4 and T 6 is the lower bridge arm;
[0037] The DC output terminal of the rectifier 1 is connected in parallel with the DC filter capa...
specific Embodiment approach 2
[0059] Specific implementation mode two: this implementation mode further explains implementation mode one. In step one, a hybrid system current observer is used to observe the current signal of the permanent magnet synchronous motor 5, and obtain the current observation value i ^ = i ^ a i ^ b i ^ c T , The process is:
[0060] by model Observing the current signal of the permanent magnet synchronous motor 5,
[0061] in: for d...
specific Embodiment approach 3
[0068] Specific implementation mode 3: This implementation mode further explains the implementation mode 1. In step 3, the α-axis current residual β axis current residual Obtained according to the following formula:
[0069] i ~ α i ~ β = 2 3 1 - 1 2 - 1 2 0 3 / ...
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