A Method for Existence and Stability Analysis of Power Flow Solution in DC Distribution System
A technology of DC power distribution and analysis method, applied in the direction of AC network circuits, circuit devices, AC networks with the same frequency with different sources, etc. Achieve accurate upper limit of load, reduce conservatism, and achieve a wide range of effects
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Embodiment 1
[0052] Provided is a method for analyzing the existence and stability of power flow solutions of DC power distribution systems. The DC power distribution system is a network structure composed of n converter nodes and m load nodes. The converter nodes and load nodes connected, adjacent load nodes are electrically connected; the analysis method includes the following steps:
[0053] S10. Using graph theory, perform equivalent topology on the DC power distribution system to obtain the transmission network admittance matrix Y; according to Ohm's law, obtain the current injected into the transmission network by each node [i s ,i L ] T , where i s is the output current of the converter node, i L Current injected into the network for load nodes;
[0054] S20. When the converter is under droop control, calculate and obtain the output voltage u s the expression;
[0055] S30. Based on the output voltage u S The expression of the constant power load and the volt-ampere character...
Embodiment 2
[0089] This embodiment is an application example of Embodiment 1. In this embodiment, a DC power distribution system including 10 converters and 20 loads is built. The converter nodes are marked with numbers 1-10, and the load nodes are marked with numbers 11-20. , the resistance between the converter node and the load node, and the resistance between the load nodes are marked in figure 1 middle. This embodiment provides six calculation examples and a comparative calculation example:
[0090] Calculation example 1: Assume that the maximum load vector of the DC power distribution system is P max =10 4 [10 10 10 10 10 8 8 8 88 10 10 10 10 10 10 12 12 12 12] T W, take the sag coefficient as k 1 =k 2 =...=k 10 =2. Then, when the voltage of the converter satisfies Equation (7), the system has a power flow feasible solution. take v 1 =v 2 =…=v 10 =2463V.
[0091] Calculation example 2: The maximum load vector is the same as the calculation example 1, take v 1 =v 2 =24...
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