LED constant-current source and control method thereof
A technology of constant current source and power supply, applied in the field of light emitting diode (LED) constant current source and its control, can solve the problems of high-voltage MOS tube heating and low efficiency, avoid excessive heating, improve utilization, solve no-load and The effect of the short circuit problem
- Summary
- Abstract
- Description
- Claims
- Application Information
AI Technical Summary
Problems solved by technology
Method used
Image
Examples
no. 1 example
[0042] pass Figure 4 It can be known from the circuit in that the current flowing through the output capacitor C1 and the load LEDs will flow through the sampling resistor Rcs; by integrating the voltage on the sampling resistor Rcs, the integral comparison level is a reference level V REF (the value of the reference level VREF in the figure), the integral resistor R3, and the integral capacitor C2. Therefore, when the voltage on the sampling resistor Rcs is relatively high, its sampling voltage is the same as the reference level V REF The difference value discharges the capacitor C2 through the resistor R2; when the voltage on the sampling resistor Rcs is relatively low, its sampling voltage is the same as the reference level V REF The difference is charged to the capacitor C2 through the resistor R2.
[0043] When the average voltage on the sampling resistor Rcs and the reference reference voltage V REF When consistent, the system is in a stable state; when stable, the l...
no. 2 example
[0051] It can be seen from the figure that the voltage on the output capacitor C1 gradually rises after power-on, and at this time there is no current on the load LEDs or the current does not reach the set value until the voltage on the output capacitor C1 makes the current on the load LEDs reach After setting the value, the voltage on the output capacitor C1 tends to be stable.
[0052] When the AC input rectified half-wave voltage is less than the voltage on the output capacitor, the voltage drop on the resistor R2 is the AC AC input rectified half-wave voltage signal, and the voltage drop on R1 is close to zero, the output terminal of the third operational amplifier Buffer The generated source current I1 is amplified to follow the current I2 by mirroring multiples, so that the negative input terminal of the second comparator CPA is zero to the floating ground potential, so the switch Q1 is turned on.
[0053] When the AC input rectified half-wave voltage is greater than the...
PUM
Login to View More Abstract
Description
Claims
Application Information
Login to View More 