Preparation method of thioether compound
A technology of compound and mercapto compound, which is applied in the field of preparation of thioether compounds, can solve the problems of short reaction time, environmental pollution, and low cost, and achieve the effects of short reaction time, cheap raw materials, and easy operation
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Embodiment 1
[0040] Add 20mg of styrene and 24mg of p-methylthiophenol into a clean and dry round bottom flask, then add 2mL of dichloromethane, slowly add 49mg of iodotrimethylsilane at room temperature, stir the reaction for no more than 15 minutes, and finally pass through the column Chromatographic separation afforded the product as a clear liquid. This liquid is carried out proton nuclear magnetic resonance spectrum, carbon spectrum analysis, is determined to be corresponding sulfide compound 1, and productive rate is 95%, its hydrogen nuclear magnetic resonance spectrum, carbon spectrum analysis results see respectively Figure 1~2 .
[0041] Depend on Figure 1~2 As can be seen, this thioether compound-test result is as follows: 1 H NMR (400MHz, CDCl 3 )δ7.40–7.31(m,4H),7.30–7.27(m,3H),7.11(m,2H),4.35(q,J=7.0Hz,1H),2.37(s,3H),1.69(d ,J=7.0Hz,3H). 13 C NMR (101MHz, CDCl 3 ) δ 143.41, 137.41, 133.26, 131.34, 129.54, 128.41, 127.37, 127.12, 48.44, 22.27, 21.21.
Embodiment 2
[0043] Add 36mg of m-bromostyrene and 29mg of p-methylthiophenol into a clean and dry round bottom flask, then add 2mL of toluene, slowly add 46mg of iodotrimethylsilane at room temperature, stir the reaction for no more than 15 minutes, and finally pass through the column Chromatographic separation afforded the product as a clear liquid. This liquid is carried out hydrogen nuclear magnetic resonance spectrum, carbon spectrum analysis, is determined to be corresponding sulfide compound two, and productive rate is 90%, its hydrogen nuclear magnetic resonance spectrum, carbon spectrum analysis results see respectively Figure 3-4 .
[0044] Depend on Figure 3-4 As can be seen, this thioether compound two test results are as follows: 1 H NMR (400MHz, CDCl 3 )δ7.44–7.42(m,1H),7.40–7.34(m,1H),7.24–7.19(m,3H),7.18–7.11(m,1H),7.12–7.03(m,2H).,4.23 (q,J=7.0Hz,1H),2.36(d,J=11.7Hz,3H),1.62(d,J=7.0Hz,3H). 13 C NMR (101MHz, CDCl 3 ) δ 145.84, 137.80, 133.52, 130.61, 130.41, 130.12,...
Embodiment 3
[0046] Add 36mg of p-bromostyrene and 29mg of p-methylthiophenol into a clean and dry round bottom flask, then add 2mL of dichloromethane, slowly add 24mg of trimethylchlorosilane at -10°C, and stir for no more than 15 minutes , and finally separated by column chromatography to obtain a transparent liquid product. This liquid is carried out H NMR spectrum, carbon spectrum analysis, is determined to be corresponding sulfide compound three, and yield rate is 93%, its H NMR spectrum, carbon spectrum analysis results see respectively Figure 5-6 .
[0047] Depend on Figure 5-6 As can be seen, the three test results of the thioether compounds are as follows: 1 H NMR (400MHz, CDCl 3 )δ7.45–7.37(m,2H),7.20(d,J=8.1Hz,2H),7.18–7.13(m,2H),7.07(d,J=8.0Hz,2H),4.25(q,J =7.0Hz, 1H), 2.34(s, 3H), 1.62(d, J=7.0Hz, 3H). 13 C NMR (101MHz, CDCl 3 ) δ 142.57, 137.70, 133.41, 131.41, 130.70, 129.59, 129.04, 120.73, 47.86, 22.05, 21.16.
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