Method for eliminating temperature gradient in metal strip sample heat treatment test

A technology of temperature gradient and metal strip, applied in the field of metal heat treatment, can solve the problems of large temperature gradient, huge equipment, high price, etc., and achieve the effect of increasing the length of the uniform temperature zone, reducing the production cost, and improving the test accuracy.
CN1731132AInactive Publication Date: 2006-02-08NORTHEASTERN UNIV LIAONING
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Patent Information

Authority / Receiving Office
CN · China
Patent Type
Applications(China)
Current Assignee / Owner
NORTHEASTERN UNIV LIAONING
Publication Date
2006-02-08
Estimated Expiration
Not applicable · inactive patent

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Abstract

The invention relates to a method for erasing temperature gradient in mental plate with sample heat treating experiment, which is characterized in that it adds infrared radiation heating means based on the mode of directly using the resistance to heat; it fixes infrared heating apparatus on the two sides of the sample near the clamp, and uses the infrared radiation energy of the infrared heating apparatus to compensate the heat leaked by heat transmitting; it separately controls the directly resistance heating and the infrared radiation heating.
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Description

technical field

[0001] The invention relates to the technical field of metal heat treatment, in particular to a method for eliminating temperature gradients in heat treatment tests of metal strip samples. Background technique

[0002] At present, many material physics simulation equipment, such as thermal simulation test machine, cold-rolled strip continuous annealing simulation test machine, etc., in order to achieve the purpose of rapid metal heating, usually use direct resistance heating, that is, use a heating transformer to provide a certain voltage for the sample. Make a large current pass through the sample, and use the resistance of the sample to achieve the purpose of heating. Since the sample is clamped between two water-cooled fixtures, a large temperature gradient is likely to occur due to heat conduction ΔT = ( 2 x L ...

Claims

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