Method for sequencing and detecting fetal genetic variation by using polymorphic site and target site
A genetic variation and locus technology, applied in the field of single nucleotide locus variation, can solve the problems of not being able to detect chromosomal and subchromosomal variation at the same time, different, non-invasive detection methods are not very sensitive and specific, etc. Achieving good development and application prospects
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Embodiment 1
[0108] For biological maternal plasma DNA samples, the minimum component is fetal DNA and the maximum component is maternal DNA. Since the fetus inherits the genetic material on the chromosome of the biological mother, each polymorphic site in the plasma DNA of the biological mother may be one of the five genotypes, and the concentration of fetal DNA can be estimated through iteration according to the above steps.
[0109] figure 2 is a flow chart for estimating fetal DNA concentrations in plasma DNA samples from pregnant women legally permitted to receive egg donation as described in Example 13.
[0110] Example 14. Estimation of fetal DNA concentration using simulated sequencing of polymorphic sites in maternal plasma DNA samples
The method and steps for estimating the concentration of fetal DNA in the sample by using the relative ratio method of allele counts are briefly described below by taking the counts of each allele of five hypothetical polymorphic sites in the s...
Embodiment 2
[0118] For site Id003, R2 / (R1+R2)=0.496≥0.01, R3 / (R1+R2+R3)=0.009<0.01, the number of alleles is estimated to be two, because R1 / (R1+R2)=0.504 <0.5+α, the genotype is estimated to be AB|AB, FC=NA, TC=R1+R2=6249.
[0119] For site Id004, R2 / (R1+R2)=0.379≥0.01, R3 / (R1+R2+R3)=0.003<0.01, the number of alleles is estimated to be two, because 0.5+α≤R1 / (R1+ R2)=0.621<0.75, the genotype is estimated to be AB|AA, FC=R1-R2=2257, TC=R1+R2=9361.
[0120] For site Id005, R2 / (R1+R2)=0.430≥0.01, R3 / (R1+R2+R3)=0.126≥0.01, the number of alleles is estimated to be two, because R2 / R1=0.756≥0.5, the gene The type estimate is AB|AC, FC=R1-R2+R3=1990, TC=R1+R2+R3=8046.
[0121] (3) Estimate the concentration of fetal DNA
[0122] 1) Enter the values of FC and TC
[0123] Estimation method Estimated fetal DNA concentration linear regression 0.2441 Robust regression 0.2441 median of ratios 0.2465 average ratio 0.2450 median ratio 0.2473 ratio of m...
Embodiment 3
[0128] (a) For each polymorphic locus, according to each allele count and f 0 , According to the method described in Example 11 and Example 12, the genotype of the locus was estimated, and theoretically the amplification count (FC) derived from fetal DNA and the total count (TC) derived from maternal and fetal DNA.
[0129] For example, for site number Id0006, R1 to R4 are 3322, 936, 36 and 28 respectively, then O 1 =3322,O 2 =936, O 3 =36,O 4 =28. Since R2 / (R1+R2)≥0.01 and R3 / (R1+R2+R3)<0.01, this locus has two detected allele numbers above the noise threshold.
[0130] The goodness of fit test for all possible genotypes at this locus is as follows:
AA|AA: TC=R1+R2=4258, E 1 =(1-α)×TC=4215.42, E 2 =α×TC=42.58,
[0131] AA|AB: TC=R1+R2=4258, E 1 =(1-f 0 / 2)×TC=4045.10, E 2 = f 0 / 2×TC=212.90,
[0132] AB|AA: TC=R1+R2=4258, E 1 =(1+f 0 ) / 2×TC=2341.90, E 2 =(1-f 0 ) / 2×TC=1916.10,
[0133] AB|AB: TC=R1+R2=4258, E 1 =1 / 2×TC=2129.00, E 2 =1 / 2×TC=212...
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