Cardanol derivative curing agent and preparation method thereof
A technology of cardanol and its derivatives, which is applied in the field of curing agent and its preparation, can solve the problems of non-environmental protection and low performance of the curing agent, and achieve the effects of good curing effect, strong environmental performance and excellent adhesion
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specific Embodiment approach 1
[0026] Specific embodiment one: a kind of cardanol derivative curing agent of the present invention, its general structural formula is:
[0027]
[0028] Wherein said R is -CH 2 CH 2 OH, -CH 2 CH 2 NH 2 、-C 6 h10 NH 2 、-C 2 h 4 NHC 2 h 4 NH 2 、-C 2 h 4 NHC 2 h 4 NHC 2 h 4 NH 2 ,-(CH 2 ) 6 NH 2 ,-(CH 2 ) 6 NH(CH 2 ) 6 NH 2 、-CH 2 C 6 h 10 CH 2 NH 2 、-CH 2 C 6 h 4 CH 2 NH 2 、-CH 2 C 6 h 4 NH 2 、-C 6 h 4 CH 2 C 6 h 4 NH 2 or -C 6 h 10 CH 2 C 6 h 10 NH 2 , said n is 2≤n≤6.
specific Embodiment approach 2
[0029] Specific embodiment two: the difference between this embodiment and specific embodiment one is that a kind of preparation method of cardanol derivative curing agent in this embodiment is to be completed according to the following steps:
[0030] 1. Preparation of Epoxypropyl Cardanol Ether: Weigh cardanol and epichlorohydrin at a molar ratio of 1: (1.3-1.5), add the weighed cardanol into a three-neck bottle, and stir Heating to 50°C-55°C at a rate of 500r / min-1000r / min, adding the weighed epichlorohydrin at a titration rate of 3mL / min-4mL / min, and then reacting under the condition of 50°C-55°C 2h to 3h, then add 25mL of sodium hydroxide solution with a mass concentration of 15%, reflux and condense for 2h to 3h, and drop 25mL of a mass concentration of 15% sodium hydroxide, reflux and condense for 2h to 3h to obtain solution A, lower solution A to room temperature, extract solution A with ethyl acetate, separate the organic layer, extract three times, then wash the orga...
specific Embodiment approach 3
[0036] Specific embodiment three: the difference between this embodiment and specific embodiment one or two is: the molar ratio of cardanol and epichlorohydrin described in step one is 1:1.4. Others are the same as in the first or second embodiment.
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