Low-expansion phosphate ceramic material and preparation method thereof
A ceramic material and phosphate technology, applied in the field of low-expansion ceramics, can solve problems affecting mechanical properties, low thermal expansion coefficient, and low density, and achieve high sintering temperature, good thermal shock resistance, and high temperature resistance.
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Embodiment 1
[0016] (1) Calculate raw material CaCO according to x=0.03 3 , SrCO 3 、C 16 h 36 o 4 Ti, ZrOCl 2 ·8H 2 O and (NH 4 ) 2 HPO 4 quality, and then weighed with a balance. ZrOCl 2 ·8H 2 O was dissolved in distilled water to prepare an aqueous solution with a concentration of 0.6mol / L; the C 16 h 36 o 4 Ti was dissolved in ethanol and prepared into a 0.5mol / L ethanol solution; (NH 4 ) 2 HPO 4 Dissolved in distilled water to prepare an aqueous solution with a concentration of 1mol / L. CaCO 3 and SrCO 3dissolved in ZrOCl 2 ·8H 2 O aqueous solution, prepared as CaCO 3 , SrCO 3 and ZrOCl 2 ·8H 2 Aqueous solution of O salt, and C 16 h 36 o 4 Ti ethanol solution was added to the above CaCO 3 , SrCO 3 and ZrOCl 2 ·8H 2 In the aqueous solution of O salt, the formation simultaneously contains Ca 2+ 、Sr 2+ 、Ti 4+ 、Zr 4+ mixed solution. The above mixed solution was added dropwise to (NH 4 ) 2 HPO 4 In the aqueous solution, ammonia water was added dropwise ...
Embodiment 2
[0018] (1) Calculate raw material CaCO according to x=0.1 3 , SrCO 3 、C 16 h 36 o 4 Ti, ZrOCl 2 ·8H 2 O and (NH 4 ) 2 HPO 4 quality, and then weighed with a balance. ZrOCl 2 ·8H 2 O was dissolved in distilled water to prepare an aqueous solution with a concentration of 0.8mol / L; the C 16 h 36 o 4 Ti was dissolved in ethanol to prepare a 0.6mol / L ethanol solution; (NH 4 ) 2 HPO 4 Dissolved in distilled water to prepare an aqueous solution with a concentration of 1mol / L. CaCO 3 and SrCO 3 dissolved in ZrOCl 2 ·8H 2 O aqueous solution, prepared as CaCO 3 , SrCO 3 and ZrOCl 2 ·8H 2 Aqueous solution of O salt, and C 16 h 36 o 4 Ti ethanol solution was added to the above CaCO 3 , SrCO 3 and ZrOCl 2 ·8H 2 In the aqueous solution of O salt, the formation simultaneously contains Ca 2+ 、Sr 2+ 、Ti 4+ 、Zr 4+ mixed solution. The above mixed solution was added dropwise to (NH 4 ) 2 HPO 4 In the aqueous solution, ammonia water was added dropwise during ...
Embodiment 3
[0020] (1) Calculate raw material CaCO according to x=0.16 3 , SrCO 3 、C 16 h 36 o 4 Ti, ZrOCl 2 ·8H 2 O and (NH 4 ) 2 HPO 4 quality, and then weighed with a balance. ZrOCl 2 ·8H 2 O was dissolved in distilled water to prepare an aqueous solution with a concentration of 1mol / L; the C 16 h 36 o 4 Ti was dissolved in ethanol to prepare a 0.8mol / L ethanol solution; the (NH 4 ) 2 HPO 4 Dissolved in distilled water to prepare an aqueous solution with a concentration of 1.2mol / L. CaCO 3 and SrCO 3 dissolved in ZrOCl 2 ·8H 2 O aqueous solution to prepare CaCO 3 , SrCO 3 and ZrOCl 2 ·8H 2 Aqueous solution of O salt, and C 16 h 36 o 4 Ti ethanol solution was added to the above CaCO 3 , SrCO 3 and ZrOCl 2 ·8H 2 In the aqueous solution of O salt, the formation simultaneously contains Ca 2+ 、Sr 2+ 、Ti 4+ 、Zr 4+ mixed solution. The above mixed solution was added dropwise to (NH 4 ) 2 HPO 4 In the aqueous solution, ammonia water was added dropwise duri...
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