Method fermenting fungal hyphae to highly yield fungal polysaccharides
A technology of fungal polysaccharide and mycelium, which is applied to the field of high-yield fungal polysaccharide fermented by fungal mycelium, can solve the problems of low yield and high cost of fungal polysaccharide, and achieve the effects of high-yield exopolysaccharide, shortening fermentation period and improving utilization rate.
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specific Embodiment approach 1
[0019] Specific embodiment one: what this embodiment mode records is a kind of method for fungal hyphae fermentation high-yield fungal polysaccharide, described method steps are as follows:
[0020] Step 1: Purchasing bacterial strains from Xinghua Fungi Research Institute, Gutian County, Fujian Province;
[0021] Step 2: Prepare slant preservation medium: take 200 g peeled potatoes and cut them into small pieces, add 800 mL of distilled water, boil for 20-30 min, filter with gauze to obtain the filtrate, add 20 g of glucose, 1 g of peptone, and 1 g of KH to the filtrate 2 PO 4 , 0.5g MgSO 4 ·7H 2 O. 20g of agar, heat to dissolve, add water to a total volume of 1L, keep the pH natural, and sterilize at 115°C for 20-30 minutes;
[0022] Step 3: Activating the strain: Inoculate the strain in Step 1 on the slant preservation medium in Step 2, culture at 22.5-25.5°C for 4-8 days, and obtain mycelium after culture;
[0023] Step 4: Preparation and cultivation of liquid seed med...
specific Embodiment approach 2
[0028] Specific embodiment two: the method for a kind of fungal hyphae fermentation high-yield fungal polysaccharide described in specific embodiment one, in step one, described bacterial strain is mushroom 881, Pleurotus eryngii 90, Tea tree mushroom No. 2, Flammulina velutipes 991 or bamboo Sun D02.
specific Embodiment approach 3
[0029] Embodiment 3: The method for fermenting high-yield fungal polysaccharides by fungal hyphae described in Embodiment 1, in step 5, the plant used in the plant extract is a plant of the genus Runnan.
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