A kind of aldehyde-free light particle board and preparation method thereof
A particleboard and lightweight technology, applied in the field of lightweight particleboard, fiberboard, and aldehyde-free light-weight man-made panels, can solve problems such as affecting product production efficiency and production cost, affecting the effect of plate-making on the surface of the plate, and uneven distribution of EPS particles, etc. Achieve the effect of improving the efficiency of plate making, facilitating indoor movement, and shortening the time of hot pressing
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Embodiment 1
[0059] To prepare terephthalic acid-modified polyether polyol, the molar ratio of -COOH in terephthalic acid to -OH of polyether polyol is 1:1, and the steps are:
[0060] Add polyether polyol (respectively 50g R2303 or 83.3g R2305 or 116.7gR2307 or 166.7R2310) in the reactor, be warming up to 80 ℃, slowly drip 166.1g terephthalic acid and 0.02g dibutyltin dilaurate successively. The mixture was heated to 140°C, reacted for 1 h, evacuated to an absolute pressure of 90Pa at 105°C, and a small amount of water was removed to obtain a terephthalic acid-modified polyether polyol (according to the added polyether polyol, respectively terephthalic acid modified R2303, R2305, R2307 or R2310).
Embodiment 2
[0062] To prepare phthalic acid-modified polyether polyol, the molar ratio of -COOH in phthalic acid to -OH of polyether polyol is 1.03:1, and the steps are:
[0063] Add polyether polyol (respectively 50g R2303 or 83.3g R2305 or 116.7gR2307 or 166.7R2310) in the reactor, be warming up to 80 ℃, slowly add 169.5g phthalic acid and 0.01g two (dodecyl sulfide) successively ) dibutyltin, heated to 138°C, and reacted for 1.5h, evacuated at 105°C to an absolute pressure of 100Pa, removed a trace amount of water, and then the polyether polyol modified by phthalic acid (according to the added polyether polyol) alcohol to obtain phthalic acid-modified R2303, R2305, R2307 or R2310, respectively.
Embodiment 3
[0065] To prepare isophthalic acid-modified polyether polyol, the molar ratio of -COOH in isophthalic acid to -OH of polyether polyol is 1.05:1, and the steps are as follows:
[0066] Add polyether polyol (respectively 50g R2303 or 83.3g R2305 or 116.7g R2307 or 166.7g R2310) in the reactor, be warming up to 80 ℃, slowly add 174.4g isophthalic acid and 0.03g stannous octoate successively, be warming up to 142 ℃, and react for 0.8h, vacuumize to 80Pa absolute pressure at 103 ℃, remove a trace amount of water, and then prepare isophthalic acid-modified polyether polyol (isophthalic acid is prepared according to the polyether polyol added). Formic acid modified R2303, R2305, R2307 or R2310).
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