Electrical insulating resin and preparation method and application thereof
An electrical insulation and resin technology, applied in the field of electrical insulation resin and its preparation, can solve the problems of weakening electrical resistance and achieve the effects of high temperature resistance, high electrical insulation, good operability and thixotropy
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Embodiment 1
[0052] Preparation of electrically insulating photocurable resins.
[0053] 1. Form a photosensitive group.
[0054] unsaturated organic acid and alcohol CH2=CH-C(=O)-OH without conjugated unsaturated system, under the action of phosphoric acid, heated to 90°C, and reacted for 8 hours to obtain a photosensitive group.
[0055] 2. Light-curing resin that forms electrical insulation.
[0056] Compounds that will contain a core ring structure Under the action of sulfuric acid, it is heated to 90° C., reacted for 8 hours, and the two ends are connected with the above-mentioned photosensitive groups, that is, it is obtained.
[0057] The above preparation process is as figure 1 shown.
Embodiment 2
[0059] Preparation of electrically insulating epoxy resins.
[0060] 1. Catalytic ring opening.
[0061] Will After mixing with epichlorohydrin, it was heated to 70°C, and Lewis acid was added to catalyze ring opening.
[0062] 2. Catalytic closed loop.
[0063] Sodium hydroxide was added, the temperature of the reaction system was controlled at 70 °C, the catalyzed ring was closed, and the infrared spectrum was measured after stirring until the infrared spectrum was 910 cm -1 The peak area at 744cm -1 When the spectral peak at the place disappears completely, the reaction is terminated, and the obtained reaction mixture is taken out, filtered, washed and distilled to obtain a bifunctional electrical insulating epoxy resin.
[0064] The above preparation process is as figure 2 shown.
experiment example
[0066] Electrical insulation performance verification experiment.
[0067] 1. The material obtained in Example 1 is made into a sample block to be tested with a thickness of 0.73mm. The resin block under this thickness has a leakage current coefficient of 1000V / 0.02mA, that is, every time the leakage current increases by 0.02mA, the corresponding resistance The voltage value is increased by 1000V;
[0068] 2. On the central position of the above-mentioned sample block to be tested, paste tin foil tape with a thickness of about 0.5mm from both sides according to the aligned positions, so that the tin foil tape on both sides becomes the electrodes attached to both sides of the sample block to be tested. Then connect them to the two electrodes of the withstand voltage tester respectively;
[0069] 3. Set the range of the withstand voltage tester to 5.0KV, and measure the leakage current value of the sample block to be tested when the voltage is 3.0kVAC, 4.0kVAC, and 5.0kVAC resp...
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