Film material for realizing photostimulation response through pi-conjugation regulation and control as well as preparation method and application
A thin-film material and light-stimulation technology, applied in luminescent materials, color-changing fluorescent materials, chemical instruments and methods, etc., can solve the problem of single-sided influence on performance, achieve cheap and easy availability, expand design ideas and application prospects, raw materials cheap effect
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Embodiment 1
[0072] Solution preparation of host molecule (I) polymethyl methacrylate (PMMA)
[0073] Weigh 10g PMMA and place it in a dry and clean 250mL round bottom flask, add 100mL tetrahydrofuran solvent, take a clean glass stopper to block the bottle mouth, and avoid solvent volatilization. After the sample is completely dissolved, a concentration of 100mg / mL of no color transparent solution.
Embodiment 2
[0075] S1. Synthesis of guest molecule (II) N,N-diphenyl-2-naphthylamine
[0076]
[0077] Weigh N,N-diphenyl-2-naphthylamine (2.19g, 10mmol), 2-bromonaphthalene (1.25mL, 12mmol), palladium acetate (112.6mg, 0.5mmol), tri-tert-butylphosphine (0.5mL , 0.25mmol) and potassium tert-butoxide (1.68g, 15mmol) in a 250mL reaction flask, vacuum-dried for 0.5h, added 80mL of anhydrous oxygen-free toluene solvent, heated to reflux under nitrogen protection, and stirred for 12h. After the reaction, it was extracted and washed with water, separated by silica gel column chromatography (eluent: petroleum ether:dichloromethane=7:3), and purified to obtain pure white solid (II) (2.52g, 85.3%). figure 1 show 1 H NMR (400MHz, CDCl 3 )δ7.75(d, J=8Hz, 1H), 7.71 (d, J=8.8Hz, 1H), 7.58(d, J=8Hz, 1H), 7.42(d, J=2.4Hz, 1H), 7.41 -7.32(m,2H),7.29-7.24(m,5H),7.13(dd,J 1 =7.6Hz,J 2 =1.2Hz,4H),7.04(tt,J 1 =8.6Hz,J 2 =1.2Hz,2H). figure 2 show 13 C NMR (100MHz, CDCl 3 )δ147.77, 145.45, 134.39...
Embodiment 3
[0081] S1. Synthesis of guest molecule (III) N-phenyl-2,2-dinaphthylamine
[0082]
[0083] The synthesis method of the guest molecule (III) is the same as that of the guest molecule (II). Figure 5 show 1 H NMR (400MHz, CDCl 3 )δ7.78(d, J=7.6Hz, 1H), 7.75(d, J=8.8Hz, 1H), 7.60(d, J=8Hz, 1H), 7.48(d, J=2.4Hz, 1H), 7.43-7.28(m,4H),7.19(dd,J 1 =9.6Hz,J 2 =1.2Hz,1H),7.08(tt,J 1 =8.4Hz,J 2 =1.2Hz,1H). Figure 6 show 13 C NMR (100MHz, CDCl 3 )δ147.71, 145.43, 134.41, 130.13, 129.33, 128.94, 127.56, 126.95, 126.28, 124.57, 124.54, 124.51, 123.13, 120.53. Figure 7 The HPLC spectrum is shown. Figure 8 Show HRMS (ESI) m / z calcd for C 22 h 18 N + (M+H) + 346.1551,found 346.1590.
[0084] S2. Weigh 5 mg of the guest molecule (III) in step S1, and put it into a clean and dry container.
[0085] S3. Measure 1 mL of the main body (I) solution in Example 1, dissolve the sample weighed in step S2 with a doping ratio of 5% by mass fraction, and disperse it evenly by ultra...
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