1,2,3-Triazole unit-based micro-molecular luminescent material and application thereof
A technology of luminescent materials and small molecules, applied in luminescent materials, electrical components, circuits, etc., can solve the problems of low exciton utilization of ordinary fluorescent materials, and achieve molecular weight determination, low sublimation temperature, and good reproducibility
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Embodiment 1
[0026] This example prepares the small molecule luminescent material P1, and its reaction is shown in the following formula:
[0027]
[0028] The specific implementation steps are: under a nitrogen atmosphere, add intermediate 1 (4,5-bis(4-bromophenyl)-2-phenyl-2H-1,2,3-triazole) to a 20mL three-necked flask ( 1.365g, 3mmol) and diphenylamine (1.268g, 7.5mmol), then add 15mL of 1,3-dimethyl-3,4,5,6-tetrahydro-2-pyrimidinone, stir, after being completely dissolved, go to Add ethylene iodide (1.433g, 7.5mmol) potassium carbonate (2.070g, 15mmol), 1,3-dimethyl-3,4,5,6-tetrahydro-2-pyrimidinone 1,4,7 , 10,13,16-hexaoxacyclooctadecane (0.792g, 3mmol), heated to 190°C, reacted for 24 hours, cooled the reaction system to room temperature, extracted with dichloromethane, and used petroleum ether: dichloromethane = 2:1 ratio of eluent was subjected to silica gel column chromatography to obtain 806 mg of white solid with a yield of 42.67%. C 44 h 33 N 5 M / S=631.27 Theoretical v...
Embodiment 2
[0033] This example prepares the small molecule luminescent material P2, and its reaction is shown in the following formula:
[0034]
[0035] The specific implementation steps are as follows: the diphenylamine in Example 1 is replaced with equivalent 4,4'-di-tert-butyldiphenylamine, and other raw materials and steps are the same as in Example 1 to obtain 1345 mg of white solid product with a yield of 48.87%. . C 60 h 65 N 5 M / S=855.52m / z: 855.52 (100.0%), 856.53 (65.6%), 857.53 (21.2%), 858.53 (4.7%), 856.52 (1.8%), 857.52 (1.2%) C, 84.17; H, 7.65; N, 8.18.
Embodiment 3
[0037] This example prepares the small molecule luminescent material P3, and its reaction is shown in the following formula:
[0038]
[0039] The specific implementation steps are as follows: the diphenylamine in Example 1 is replaced by an equivalent amount of carbazole, and other raw materials and steps are the same as in Example 1 to obtain 872 mg of a white solid product with a yield of 46.29%. C 44 h 29 N 5 M / S=627.24 Theoretical values: 627.24 (100.0%), 628.25 (47.9%), 629.25 (11.2%), 630.25 (1.9%), 628.24 (1.8%). C, 84.19; H, 4.66; N, 11.16.
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