Synthesis method for salidroside and intermediate compound obtained in synthesis method
A synthesis method and technology of salidroside, which are applied in the directions of esterification saccharides, chemical instruments and methods, sugar derivatives, etc., can solve the problems of difficult glycosidation reaction, high time and cost consumption, and no protection of phenolic hydroxyl groups. , to achieve the effect of simplifying the operation steps and processing technology, the safety of human medicine, and avoiding by-products
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[0060] Example 1
[0061] (1) Intermediate II (R 1 Is pivaloyl, R 2 Is the synthesis of trifluoroacetyl)
[0062] Add 60g (0.1mol) pentapivaloyl glucose, 300ml of acetic acid, 21g of trifluoroacetic anhydride, 40ml of boron trifluoride ether to a 500ml three-necked flask, heat to reflux for 10h, after the reaction is complete, cool, pour into 1L of water for crystallization, and filter , Washed with water to neutral, dried under reduced pressure at 60°C to obtain 53.3g of white solid, yield 87.1%, 1 H-NMR(300MHz, CDCl 3 ): δ=6.42~6.40(d,1H), 5.24~5.79(m,2H,CH), 3.73~3.62(m,1H,CH), 4.27~4.14(m,1H,CH), 3.46~2.94( m, 2H), 2.56~2.48 (m, 4H, CH), 1.12 (s, 36H, CH) 3 ).
[0063] (2) Synthesis of the compound represented by formula IV (the phenolic hydroxyl group of formula III is protected by a benzoyl group, namely compound 9)
[0064] Add 33.4g (0.06mol) of Intermediate II, 10.4g (0.05mol) of Intermediate III, 120ml of acetonitrile to a 500ml three-necked flask, add 10ml of boron trifluo...
Example Embodiment
[0069] Example 2
[0070] (1) Intermediate II (R 1 Is pivaloyl, R 2 Is the synthesis of trifluoromethanesulfonyl)
[0071] Add 60g (0.1mol) pivaloyl glucose, 300ml acetic acid, 28.2g trifluoromethanesulfonic anhydride, 40ml boron trifluoride ether to a 500ml three-necked flask, heat and reflux for 10h, after the reaction is complete, cool, pour into 1L of water for crystallization, Filter, wash with water to neutral, and dry under reduced pressure at 60°C to obtain 59.4 g of white solid with a yield of 94%. 1 H-NMR(300MHz, CDCl 3 ): δ=6.82(d,1H), 5.14~5.57(m,2H,CH), 3.23~3.16(m,1H,CH), 4.17~4.08(m,1H,CH), 3.41~2.84(m, 2H), 1.22(s,36H, CH 3 ).
[0072] (2) Synthesis of compound represented by formula IV (the phenolic hydroxyl group of formula III is protected by isobutyryl group, namely compound 8)
[0073] Add 38g (0.06mol) of Intermediate II, 10.4g (0.05mol) of Intermediate III, 120ml of dichloromethane, 2.8g of zinc chloride to a 500ml three-necked flask, and react for 8h at 25~30℃...
Example Embodiment
[0076] Example 3
[0077] (1) Synthesis of Intermediate II (R1 is isobutyryl, R2 is trifluoromethylsulfonyl)
[0078] Add 53g (0.1mol) pentaisobutyryl glucose, 300ml of acetic acid, 28.2g of trifluoromethanesulfonic anhydride, 35ml of boron trifluoride ether to a 500ml three-necked flask, heat and reflux for 10h, after the reaction is complete, cool, pour into 1L of water to crystallize , Filtered, washed with water until neutral, dried under reduced pressure at 60°C to obtain 53.5g of white solid with a yield of 93%. 1 H-NMR(300MHz, CDCl 3 ): δ=6.64~6.59(d,1H,CH),5.34~5.29(m,2H,CH), 3.71~3.61(m,1H,CH), 4.23~4.16(m,1H,CH), 3.45~ 2.94 (m, 2H), 2.56~2.48 (m, 4H, CH), 1.32 (d, 24H, CH) 3 ).
[0079] (2) Synthesis of the compound represented by formula IV (the phenolic hydroxyl group of formula III is protected by an isobutyryl group, namely compound 2)
[0080] Add 34.6g (0.06mol) of Intermediate II, 11.8g (0.05mol) of Intermediate III, 120ml of nitromethane, 3.5g of zinc bromide to a 5...
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